Answer
1
Work Step by Step
$(f+g)(x)=f(x)+g(x)$
$(f+g)(x)=f(x)+g(x)=x^2-2x+x-5=x^2-x-5$
Plug in $x=-2$ into $(f+g)(x)$: $(f+g)(-2)=(-2)^2-(-2)-5=4+2-5=1$
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