Answer
3
Work Step by Step
$(f-g)(x)=f(x)-g(x)$
$(f-g)(x)=f(x)-g(x)=x^2-2x-(x-5)=x^2-3x+5$
Plug in $x=1$ into $(f-g)(x)$: $(f-g)(1)=(1)^2-3\cdot1+5=1-3+5=3$
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