Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 599: 23

Answer

$x=\dfrac{43}{21}$

Work Step by Step

Using properties of logarithms and since $\log_b x=y$ implies $b^y=x$, then, \begin{array}{l} \log_4 (x+1)-\log_4 (x-2)=3 \\\\ \log_4 \dfrac{x+1}{x-2}=3 \\\\ \dfrac{x+1}{x-2}=4^3 \\\\ x+1=64(x-2) \\\\ x+1=64x-128 \\\\ x-64x=-128-1 \\\\ -63x=-129 \\\\ x=\dfrac{-129}{-63} \\\\ x=\dfrac{43}{21} .\end{array}
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