Answer
$\log_6 2+\log_6 x-3\log y$
Work Step by Step
Using the properties of logarithms, then,
\begin{array}{l}
\log_6 \dfrac{2x}{y^3}
\\\\=
\log_6 2x-\log y^3
\\\\=
\log_6 2+\log_6 x-\log y^3
\\\\=
\log_6 2+\log_6 x-3\log y
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Test - Page 599: 14
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