Answer
$x=\dfrac{1}{9}$
Work Step by Step
Since $\log_b x=y$ implies $b^y=x$, then,
\begin{array}{l}
\log_3 x=-2
\\\\
x=3^{-2}
\\\\
x=\dfrac{1}{3^{2}}
\\\\
x=\dfrac{1}{9}
.\end{array}
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