Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 599: 22

Answer

$x=\dfrac{25}{3}$

Work Step by Step

Using properties of logarithms and since $\log_b x=y$ implies $b^y=x$, then, \begin{array}{l} \log_5 x+\log_5 3=2 \\\\ \log_5 3x=2 \\\\ 3x=5^2 \\\\ 3x=25 \\\\ x=\dfrac{25}{3} .\end{array}
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