Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 599: 18

Answer

$x=\dfrac{\log4-5\log3}{2\log3} \\\\ x\approx-1.8691 $

Work Step by Step

Getting the logarithm of both sides, then, \begin{array}{l} 3^{2x+5}=4 \\\\ \log3^{2x+5}=\log4 \\\\ (2x+5)\log3=\log4 \\\\ 2x\log3+5\log3=\log4 \\\\ 2x\log3=\log4-5\log3 \\\\ x=\dfrac{\log4-5\log3}{2\log3} \\\\ x\approx-1.8691 .\end{array}
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