Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.6 - Rational Equations and Problem Solving - Exercise Set - Page 388: 22

Answer

$7$

Work Step by Step

Let $x$ be the number. The conditions of the problem translate to the equation \begin{array}{l}\require{cancel} \dfrac{13-x}{8+x}=\dfrac{2}{5} .\end{array} By cross-multiplication and using the properties of equality, the equation above is equivalent to \begin{array}{l}\require{cancel} (13-x)5=(8+x)2 \\\\ 65-5x=16+2x \\\\ 65-16=2x+5x \\\\ 49=7x \\\\ \dfrac{49}{7}=x \\\\ x=7 .\end{array} Hence the number is $ 7 .$
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