Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.6 - Rational Equations and Problem Solving - Exercise Set - Page 388: 21

Answer

$5$

Work Step by Step

Let $x$ be the number. The conditions of the problem translate to the equation \begin{array}{l}\require{cancel} \dfrac{12+x}{41+2x}=\dfrac{1}{3} .\end{array} By cross-multiplication and using the properties of equality, the equation above is equivalent to \begin{array}{l}\require{cancel} (12+x)3=(41+2x)1 \\\\ 36+3x=41+2x \\\\ 3x-2x=41-36 \\\\ x=5 .\end{array} Hence the number is $ 5 .$
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