Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 370: 48

Answer

$P(2)=14$

Work Step by Step

Substituting $x$ with $ 2 $ in $ P(x)=x^3+5x^2-4x-6 $, then \begin{array}{l} P(2)=(2)^3+5(2)^2-4(2)-6 \\\\ P(2)=8+20-8-6 \\\\ P(2)=14 .\end{array}
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