Answer
$2x^2+2x+8+\dfrac{28}{x-4}$
Work Step by Step
Using the long division below, then
\begin{array}{l}\require{cancel}(
2x^3-6x^2-4
)\div(
x-4
)\\=
2x^2+2x+8+\dfrac{28}{x-4}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 370: 33
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