Answer
$3x+4$
Work Step by Step
Factoring the expressions and cancelling the common factors between the numerator and the denominator, the given expression, $
(3x^2+19x+20)\div(x+5)
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{3x^2+19x+20}{x+5}
\\\\=
\dfrac{(3x+4)(x+5)}{x+5}
\\\\=
\dfrac{(3x+4)(\cancel{x+5})}{\cancel{x+5}}
\\\\=
3x+4
.\end{array}
