Answer
$3x^2+4x-8+\dfrac{20}{x+1}$
Work Step by Step
Using the long division below, then
\begin{array}{l}\require{cancel}\dfrac{
7x^2-4x+12+3x^3
}{
x+1
}\\\\=
3x^2+4x-8+\dfrac{20}{x+1}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 370: 37
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