Answer
$x^3+6x^2+11x+6+\dfrac{8}{x-2}$
Work Step by Step
Using the long division below, then
\begin{array}{l}\require{cancel}\dfrac{
4x^3+x^4-x^2-16x-4
}{
x-2
}\\\\=
x^3+6x^2+11x+6+\dfrac{8}{x-2}
.\end{array}
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