Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 370: 1

Answer

$2a+4$

Work Step by Step

Divide $2a$ to each term of the dividend to have: $\require{cancel} \\=\dfrac{4a^2}{2a} + \dfrac{8a}{2a} \\=\dfrac{\cancel{4a^2}2a}{\cancel{2a}} + \dfrac{\cancel{8a}4}{\cancel{2a}} \\=2a + 4$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.