Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapters 1-9 Cumulative Review Problem Set - Page 432: 44

Answer

48

Work Step by Step

Multiplying the coefficients by each other and the radicals by each other, we obtain: $(3\sqrt 8)(4\sqrt 2)$ =$(3\sqrt 8)\times(4\sqrt 2)$ =$3(4)\times(\sqrt 2\times\sqrt 8)$ =$12\times(\sqrt {2\times8})$ =$12\times(\sqrt {16})$ =$12\times(\sqrt {4^{2}})$ =$12\times4$ =$48$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.