Answer
$-\frac{8}{x^{2}}$
Work Step by Step
Since all terms are multiplied by each other, we can collect constants and variables separately in their own parentheses. We then use the rule $a^{m}\times a^{n}=a^{m+n}$ and $\frac{1}{x^{2}}=x^{-2}$ to simplify the expression:
$(-4x^{-5})(2x^{3})$
=$(\frac{-4}{x^{5}})(2x^{3})$
=$(-4\times2)\times(\frac{x^{3}}{x^{5}})$
=$(-8)\times x^{3-5}$
=$(-8)\times x^{-2}$
=$\frac{-8}{x^{2}}$
=$-\frac{8}{x^{2}}$
