Answer
$2x(2x+5)(3x-4)$
Work Step by Step
Upon inspection, we find that the term $2x$ is common to all the terms in the expression. Therefore factor out $2x$ from each term of the expression to obtain:
$12x^{3}+14x^{2}-40x$
=$2x(6x^{2}+7x-20)$
Next, we further factor the quadratic equation within the parenthesis:
$2x(6x^{2}+7x-20)$
=$2x[(2x+5)(3x-4)]$
=$2x(2x+5)(3x-4)$
