Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapters 1-9 Cumulative Review Problem Set - Page 432: 38

Answer

$8\sqrt 7$

Work Step by Step

To simplify the expression, we will first simplify the term within the square root: $4\sqrt {28}$ =$4\sqrt {4\times7}$ =$4(\sqrt 4\times\sqrt 7)$ =$4(\sqrt {2^{2}}\times\sqrt 7)$ =$4(2\times\sqrt 7)$ =$8\sqrt 7$
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