Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapters 1-9 Cumulative Review Problem Set - Page 432: 34

Answer

$(y+3)(x-2)$

Work Step by Step

Since $x$ is common to the first two terms of the expression and $-2$ is common to the last two terms, we obtain: $xy+3x-2y-6$ =$x(y+3)-2(y+3)$ =$(y+3)(x-2)$
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