Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set - Page 430: 8

Answer

$4\sqrt 2$

Work Step by Step

Recall the following rule: $(\sqrt{x^{2}})=x$ Thus, we obtain: $\sqrt {32}=\sqrt {2\times16}=\sqrt 2\times \sqrt {16}=\sqrt 2\times \sqrt {4^{2}}=4\sqrt 2$
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