Answer
$\approx 17.3$
Work Step by Step
Using $\sqrt{3}=1.73$ and the properties of radicals, the value of the given expression, $
3\sqrt{12}+\sqrt{48}
,$ to the nearest tenth, is
\begin{array}{l}\require{cancel}
3\sqrt{4\cdot3}+\sqrt{16\cdot3}
\\\\=
3\sqrt{(2)^2\cdot3}+\sqrt{(4)^2\cdot3}
\\\\=
3\cdot2\sqrt{3}+4\sqrt{3}
\\\\=
6\sqrt{3}+4\sqrt{3}
\\\\=
10\sqrt{3}
\\\\=
10(1.73)
\\\\
\approx 17.3
.\end{array}
