Answer
$\dfrac{-2\sqrt{x}}{5}$
Work Step by Step
Using the properties of radicals, the given expression, $
\dfrac{-2\sqrt{x^2y}}{5\sqrt{xy}}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{-2}{5}\sqrt{\dfrac{x^2y}{xy}}
\\\\=
\dfrac{-2}{5}\sqrt{\dfrac{\cancel{xy}\cdot x}{\cancel{xy}}}
\\\\=
\dfrac{-2}{5}\sqrt{x}
\\\\=
\dfrac{-2\sqrt{x}}{5}
.\end{array}
Note that all variables are assumed to have positive values.
