Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set - Page 430: 7

Answer

$2\sqrt 5$

Work Step by Step

Recall the following rule: $(\sqrt{x^{2}})=x$ Thus, we obtain: $\sqrt {20}=\sqrt {4\times5}=\sqrt {2^{2}}\times \sqrt 5=2\times\sqrt 5=2\sqrt 5$
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