Answer
$\approx 5.2$
Work Step by Step
Using $\sqrt{3}=1.73$ and the properties of radicals, the value of the given expression, $
\sqrt{27}
,$ to the nearest tenth, is
\begin{array}{l}\require{cancel}
\sqrt{9\cdot3}
\\\\=
\sqrt{(3)^2\cdot3}
\\\\=
3\sqrt{3}
\\\\=
3(1.73)
\\\\
\approx 5.2
.\end{array}
