Answer
$-\frac{2}{3}$
Work Step by Step
Recall the following rule:
$(\sqrt{x})^{2}=x$
Thus, we obtain:
$-\sqrt \frac{4}{9}=-\sqrt \frac{2^{2}}{3^{2}}=-\frac{\sqrt {2^{2}}}{\sqrt {3^{2}}}=-\frac{2}{3}$
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 9 - Roots and Radicals - Chapter 9 Review Problem Set - Page 430: 5
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