Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Review Problem Set - Page 274: 40

{$-2,3$}

Since $(x+2)$ is common to both the terms of the equation, we take it out as a common factor: $3(x+2)-x(x+2)=0$ $(x+2)(3-x)=0$ Now, we equate all the factors to zero to solve the equation: $(x+2)(3-x)=0$ $x+2=0$ or $3-x=0$ $x=-2$ or $x=3$ Therefore, the solution set is {$-2,3$}.