Answer
{$8,12$}
Work Step by Step
Using the rules of factoring trinomials to factor the polynomial, we obtain:
$x^{2}-20x+96=0$
$x^{2}-8x-12x+96=0$
$x(x-8)-12(x-8)=0$
$(x-8)(x-12)=0$
Now, we equate the two factors to zero and solve:
$(x-8)(x-12)=0$
$(x-8)=0$ or $(x-12)=0$
$x=8$ or $x=12$
Therefore, the solution set is {$8,12$}.
