Answer
$(y-3)(x-2)$
Work Step by Step
Upon inspection, we find that $x$ is common to the first two terms of the expression while $-2$ is common to the last two terms of the expression, so we factor accordingly:
$xy-3x-2y+6$
=$x(y-3)-2(y-3)$
Since $(y-3)$ is now common to the expression, we factor it out:
$x(y-3)-2(y-3)=(y-3)(x-2)$
