Answer
$\left\{-1, 0, 1\right\}$
Work Step by Step
Factor out $t$ to obtain:
$t(t^2-1)=0$
Factor the difference of two squares using the formula $a^2-b^2=(a-b)(a+b)$ where $a=t$ and $b=1$ to obtain:
$t(t-1)(t+1)=0$
Equate each factor to 0 to obtain:
$t=0 \text{ or } t-1 = 0 \text{ or } t+1=0$
Solve each equation to obtain:
$t=0 \text{ or } t=1 \text{ or } t =-1$
Therefore the solution set is $\left\{-1, 0, 1\right\}$.
