Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.2 - Factoring the Difference of Two Squares - Problem Set 6.2 - Page 249: 93

$(2x-y)(4x^2+2xy+y^2)$

Using $a^3-b^3=(a-b)(a^2+ab+b^2)$ or the factoring of the difference of $2$ cubes, the factored form of the given expression, $ 8x^3-y^3 ,$ is \begin{array}{l}\require{cancel} (2x-y)[(2x)^2+2x(y)+(y)^2] \\\\= (2x-y)(4x^2+2xy+y^2) .\end{array}