Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.2 - Factoring the Difference of Two Squares - Problem Set 6.2 - Page 249: 88

$(2x+3y)(4x^2-6xy+9y^2)$

Using $a^3+b^3=(a+b)(a^2-ab+b^2)$, or the factoring of the sum of $2$ cubes, the factored form of the given expression, $ 8x^3+27y^3 ,$ is \begin{array}{l}\require{cancel} (2x+3y)[(2x)^2-2x(3y)+(3y)^2] \\\\= (2x+3y)(4x^2-6xy+9y^2) .\end{array}