Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.2 - Factoring the Difference of Two Squares - Problem Set 6.2 - Page 249: 90

$(1-2x)(1+2x+4x^2)$

Using $a^3-b^3=(a-b)(a^2+ab+b^2)$ or the factoring of the difference of $2$ cubes, the factored form of the given expression, $ 1-8x^3 ,$ is \begin{array}{l}\require{cancel} (1-2x)[(1)^2+1(2x)+(2x)^2] \\\\= (1-2x)(1+2x+4x^2) .\end{array}