Answer
{$\frac{1}{3},\frac{3}{2}$}
Work Step by Step
Using the rules for factoring trinomials, we obtain:
$6x^{2}-11x+3=0$
$6x^{2}-2x-9x+3=0$
$2x(3x-1)-3(3x-1)=0$
$(3x-1)(2x-3)=0$
$(3x-1)=0$ or $(2x-3)=0$
$x=\frac{1}{3}$ or $x=\frac{3}{2}$
Therefore, the solution set is {$\frac{1}{3},\frac{3}{2}$}.
