Answer
$13n^{\frac{7}{20}}$
Work Step by Step
Using the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$, we obtain:
$\frac{39n^{\frac{3}{5}}}{3n^{\frac{1}{4}}}$
=$\frac{39}{3}\times\frac{n^{\frac{3}{5}}}{n^{\frac{1}{4}}}$
=$13\times n^{\frac{3}{5}-\frac{1}{4}}$
=$13\times n^{\frac{3(4)-1(5)}{20}}$
=$13\times n^{\frac{12-5}{20}}$
=$13\times n^{\frac{7}{20}}$
=$13n^{\frac{7}{20}}$
