Answer
$6x^{\frac{17}{20}}$
Work Step by Step
Using the rule $a^{m}\times a^{n}=a^{m+n}$, we obtain:
$3x^{\frac{1}{4}}\times 2x^{\frac{3}{5}}$
$=(3\times2)\times(x^{\frac{1}{4}}\times x^{\frac{3}{5}})$
$=6(x^{\frac{1}{4}+\frac{3}{5}})$
$=6x^{\frac{1(5)+3(4)}{20}}$
$=6x^{\frac{5+12}{20}}$
$=6x^{\frac{17}{20}}$
