Answer
$Q(x)=x^{3}-2x^{2}+4x-8,\quad R(x)=0$
Work Step by Step
Important: zeros for missing powers of P(x).
$\left.\begin{array}{l}
-2 \ \lfloor \\ \\ \\ \end{array}\right.\begin{array}{rrrrr}
1 & 0 & 0 & 0 & -16 \\\hline
& -2 & 4 & -8 & 16 \\\hline
1 & -2 & 4 & -8 &|\ \ \ 0 \end{array}$
$Q(x)=x^{3}-2x^{2}+4x-8,\quad R(x)=0$
