Answer
$Q(x)=x^{3}+x^{2}+3x+5,\quad R(x)=12$
Work Step by Step
$\left.\begin{array}{l}
2 \ \lfloor \\ \\ \\ \end{array}\right.\begin{array}{rrrrr}
1 & -1 & 1 & -1 & 2 \\\hline
& 2 & 2 & 6 & 10 \\\hline
1 & 1 & 3 & 5 &|\ \ \ 12 \end{array}$
$Q(x)=x^{3}+x^{2}+3x+5,\quad R(x)=12$
