Answer
$Q(x)=x^{2}-6x+9,\quad R(x)=0$
Work Step by Step
$\left.\begin{array}{l}
3 \ \lfloor \\ \\ \\ \end{array}\right.\begin{array}{rrrrr}
1 & -9 & 27 & -27 & \\\hline
& 3 & -18 & 27 & \\\hline
1 & -6 & 9 & |\ \ \ 0 & \end{array}$
$Q(x)=x^{2}-6x+9,\quad R(x)=0$
