Answer
$Q(x)=x^{2}-x+2,\quad R(x)=-5$
Work Step by Step
$\left.\begin{array}{l}
\\
x+3\ )\\
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\\
\\
\\
\\
\\
\\
\\
\\
\end{array}\right. \begin{array}{rrrrr}
x^{2} & -x & +2 & & \\
\hline x^{3} & +2x^{2} & -x & +1 & \\
x^{2} & +3x^{2} & & & \\
-- & -- & & & \\
& -x^{2} & -x & +1 & \\
& -x^{2} & -3x & & \\
& -- & -- & & \\
& & 2x & +1 & \\
& & 2x & +6 & \\
& & -- & -- & \\
& & & -5 &
\end{array} $
$Q(x)=x^{2}-x+2,\quad R(x)=-5$