Answer
$Q(x)=x^{4}+1,\quad R(x)=0$
Work Step by Step
$ \left.\begin{array}{l}
\\
x^{2}+1\ )\\
\\
\\
\\
\\\\
\\
\end{array}\right. \begin{array}{lllll}
x^{4} & & & +1 & \\
\hline x^{6} & & +x^{4} & +x^{2}+1 & \\
x^{6} & & +x^{4} & & \\
-- & -- & -- & & \\
& & 0 & +x^{2}+1 & \\
& & & +x^{2}+1 & \\
& & & -- & \\
& & & 0 &
\end{array} $
$Q(x)=x^{4}+1,\quad R(x)=0$