Answer
$ f^{-1}(x) = (x - 2)^{3}$
Work Step by Step
$f(x) = 2 + \sqrt[3] x$
$y= 2 + \sqrt[3] x$
$y - 2 = \sqrt[3] x$
$(y - 2)^{3} = (\sqrt[3]x)^{3}$
$(y - 2)^{3} = x$
$(x - 2)^{3} = f^{-1}(x)$
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