Answer
$f^{-1}(x) = \frac{4x}{1 - x}$
Work Step by Step
$f(x) = \frac{x}{x + 4}$
$y = \frac{x}{x + 4}$
y(x + 4) = x
yx + 4y = x
4y = x - yx
4y = x(1 - y)
$x = \frac{4y}{1 - y}$
$f^{-1}(x) = \frac{4x}{1 - x}$
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