Answer
$f^{-1}(x) = \sqrt[5] {\sqrt[7] y + 6 }$
Work Step by Step
$f(x) = (x^{5} - 6)^{7}$
$y = (x^{5} - 6)^{7}$
$\sqrt[7] y = x^{5} - 6$
$\sqrt[7] y + 6 = x^{5}$
$\sqrt[5] {\sqrt[7] y + 6 } = x$
$\sqrt[5] {\sqrt[7] y + 6 } = f^{-1}(x)$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises - Page 263: 66
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