Answer
$f^{-1}(x) = \sqrt {4 - x}, x\geq0$
Work Step by Step
$f(x) = 4 - x^{2}$
$y= 4 - x^{2}$
$4 - y = x^{2}$
$\sqrt {4 - y} = x$
$\sqrt {4 - x} = f^{-1}(x)$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises - Page 263: 61
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