Answer
$f^{-1}(x) = \frac{2x}{x - 3}$
Work Step by Step
$f(x) = \frac{3x}{x - 2}$
$y = \frac{3x}{x - 2}$
y(x - 2) = 3x
yx - 2y = 3x
yx - 3x = 2y
x(y - 3) = 2y
$x = \frac{2y}{y - 3}$
$f^{-1}(x) = \frac{2x}{x - 3}$
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