Answer
$f^{-1}(x) = \frac{2x + 2}{1 - x}$
Work Step by Step
$f(x) = \frac{x - 2}{x + 2}$
$y = \frac{x - 2}{x + 2}$
y(x + 2) = x - 2
yx + 2y = x - 2
2y + 2 = x - yx
2y + 2 = x( 1 - y)
$x = \frac{2y + 2}{1 - y}$
$f^{-1}(x) = \frac{2x + 2}{1 - x}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises - Page 263: 54
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