College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.7 - Combining Functions - 2.7 Exercises - Page 253: 44

Answer

6

Work Step by Step

From the table, we see that: $f(2)=3$ and $g(3)=6$, so we have: $(g\circ f)(2)=g(f(2))=g(3)=6$
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