Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.3 - Solving Quadratic Equations Using Square Roots - Exercises - Page 501: 24

Answer

$x=\frac{9}{2}$ and $x=-\frac{1}{2}$

Work Step by Step

The given equation is $\Rightarrow 4(x-2)^2=25$ Divide each side by $4$. $\Rightarrow \frac{4(x-2)^2}{4}=\frac{25}{4}$ Simplify. $\Rightarrow (x-2)^2=\frac{25}{4}$ Take the square root of each side. $\Rightarrow x-2=\pm\sqrt {\frac{25}{4}}$ Simplify. $\Rightarrow x-2=\pm\frac{5}{2}$ Add $2$ to each side. $\Rightarrow x-2+2=2\pm\frac{5}{2}$ Simplify. $\Rightarrow x=2\pm\frac{5}{2}$ Two real solutions are $\Rightarrow x=2+\frac{5}{2}$ or $x=2-\frac{5}{2}$ Simplify. $\Rightarrow x=\frac{9}{2}$ or $x=-\frac{1}{2}$ Hence, the solutions are $x=\frac{9}{2}$ and $x=-\frac{1}{2}$.
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