Answer
$x=3$ and $x=-1$.
Work Step by Step
The given equation is
$\Rightarrow (x-1)^2=4$
Take the square root of each side.
$\Rightarrow x-1=\pm\sqrt {4}$
Simplify.
$\Rightarrow x-1=\pm 2$
Add $1$ to each side.
$\Rightarrow x-1+1=1\pm 2$
Simplify.
$\Rightarrow x=1\pm 2$
Two real solutions are
$\Rightarrow x=1+ 2$ or $x=1-2$
Simplify.
$\Rightarrow x=3$ or $x=-1$
Hence, the solutions are $x=3$ and $x=-1$.
